C++ Program to Check the Number is Even or Odd

This C+ +Program checks if a given integer is odd or even. Here if a given number is divisible by 2 with the remainder 0 then the number is even number. If the number is not divisible by 2 then that number will be odd number.

Here is source code of the C++ program which checks a given integer is odd or even. The C++ program is successfully compiled and run on a Linux system. The program output is also shown below.

Practice Question :

1.Wap to check the number is prime or not

2.Wap to check the character is vowel, consonants or special character.

3.Wap to find the sum of n natural numbers.

4.Wap to print all prime number in given range taking range from users.

5.Wap to print the multiplicaton table .

source code :

//even or odd
#include<iostream>
using namespace std;
int main(){
    int number;
    cout<<"Enter the number : "<<endl;
    cin>>number;
    if(number%2==0)
    cout<<"The number you entered is even"<<endl;
    else
    cout<<"The number you entered is odd"<<endl;
    return 0;
}

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